Difference between revisions of "Computer Science/61b"

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(Gameboard & chips ADT: -bb – +checked states for chips)
(Additional methods in Gameboard class: reflect changes to generateMoves)
Line 43: Line 43:
 
This is the real meat of the project.
 
This is the real meat of the project.
 
  /* Andrew */
 
  /* Andrew */
  // generates an array of Gameboards of all the possible moves from the current Gameboard g for a given player. returns an array of Gameboards
+
  // generates a 2-d array of moves and resulting gameboards for a given color
 +
// @return[0] is an array of Gameboards (Gameboard[x])
 +
// @return[1] is an array of Moves corresponding to each board in return[0] (Move[x])
 +
// thus the board after performing g.performMove(color, return[1][i]) is return[0][i]
 
  Object[][] generateMoves(Gameboard g, int color)
 
  Object[][] generateMoves(Gameboard g, int color)
 
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Revision as of 20:16, 29 October 2006

Project 2 modules

Members: Paul, -bb; Andrew, -fe; Jordan, -er

Gameboard & chips ADT

/* Paul */
// Gameboard abstract data type – Gameboard class
// fields: public static final int SDEPTH = 10, given to no-depth constructor
// methods:
// inserts a chip of the given color in the specified place as determined by an x, y coord pair
// returns true if the insertion succeeds; false otherwise
boolean insertChip(int color, int x, int y)
// move a given chip to a specified place as determined by an x, y coord pair
// returns true if the move succeeds; false otherwise
boolean moveChip(Chip c, int x, int y)
// performs a move and returns true/false depending on whether it succeeded
boolean performMove(int color, Move m)
// returns the Chip at a given location as determined by an x, y coord pair
Chip retrieveChip(int x, int y)
// returns true if the given move is valid; false otherwise
/* Verified conditions:
# No chip may be placed in any of the four corners. 
# No chip may be placed in a goal of the opposite color.
# No chip may be placed in a square that is already occupied.
# A player may not have more than two chips in a connected group, whether connected orthogonally or diagonally. */
boolean validMove(Move m)

// Chip abstract data type – Chip class
// color field stores the chip's color as a static final int; x and y fields store the chip's x and y coords, respectively
// fields: public static final int WHITE/BLACK = 1/0 (this is how we refer to colors, though I don't think anyone would need to)
//         public final static int DIMENSION = 8 for the dimensions of the board
// methods:
// returns the chip's color
int getColor()
// returns the x coord of the chip
int getX()
// returns the y coord of the chip
int getY()
// returns the checked state of the chip (used for network detection)
boolean Checked()
// sets the checked state of the chip to newval
void setChecked(boolean newval)

Additional methods in Gameboard class

This is the real meat of the project.

/* Andrew */
// generates a 2-d array of moves and resulting gameboards for a given color
// @return[0] is an array of Gameboards (Gameboard[x])
// @return[1] is an array of Moves corresponding to each board in return[0] (Move[x])
// thus the board after performing g.performMove(color, return[1][i]) is return[0][i]
Object[][] generateMoves(Gameboard g, int color)

/* Paul */
// evaluates all possible moves to be generated from the this board using the minimax algorithm and alpha-beta pruning.
// continues searching until it reaches depth or a win, whichever comes first
Move evalTree(int color, int depth)

/* Jordan */
// evaluates the given network for a winning color
// returns a probability of winning if there is no win
// returns 999 if WHITE wins, -999 if BLACK wins
int winner(Gameboard g)

Changes to MachinePlayer class

New fields

int color
int opponent
int depth
Gameboard board

Methods

As I mentioned to Jordan over e-mail, all of the methods and constructors in MachinePlayer class become pretty trivial after we write all of the methods in the Gameboard class. I (Paul) have already done all of them, so assuming everything else works as planned, we should be ok.