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Philosophy/PS2

263 bytes added, 19:29, 13 February 2009
8b
|F || F || F || T
|}
 
(b) Yes; for φ(p,p,p) = F, p = F as well.
Yes; for φ(q,p,q) = F, p = F as well.
No; there are two cases in which φ(p,φ(q,p,q),q) = F, and p = F for only one of them. Thus p = T, q = F gives us φ(p,φ(q,p,q),q) = F while p = T, so implication does not hold.
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